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A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is at the top of the wheel. Determine the angular velocity of the Ferris Wheel.

User John Judd
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1 Answer

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To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore


F_c = W-N


m\omega^2r = W-N

Here,

m = Net mass


\omega= Angular velocity

r = Radius

W = Weight

N = Normal Force


m\omega^2r = 174-146

The net mass is equivalent to


F = mg \rightarrow m = (F)/(g)

Then,


m = (174lb)/(32.17ft/s^2)

Replacing we have then,


((174lb)/(32.17ft/s^2))\omega^2 (54ft) =174lb-146lb

Solving to find the angular velocity we have,


\omega = 0.309rad/s

Therefore the angular velocity is 0.309rad/s

User Calimarkus
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