Question

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly into the wound. If 25.0 g of Ag2O is reacted with 50.0 g of C10H10N4SO2, what mass of silver sulfadiazine (AgC10H9N4SO2) can be produced, assuming 100% yield?Ag2O(s)+2C10H10N4SO2(s)⟶2AgC10H9N4SO2(s)+H2O(l)

Answer 1

Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.

Solution : Given,

Mass of
`Ag_2O` = 25.0 g

Mass of
`C_(10)H_(10)N_4SO_2` = 50.0 g

Molar mass of
`Ag_2O` = 231.7 g/mole

Molar mass of
`C_(10)H_(10)N_4SO_2` = 250.3 g/mole

Molar mass of
`AgC_(10)H_(9)N_4SO_2` = 357.1 g/mole

First we have to calculate the moles of
`Ag_2O` and
`C_(10)H_(10)N_4SO_2`.

`\text{ Moles of }Ag_2O=\frac{\text{ Mass of }Ag_2O}{\text{ Molar mass of }Ag_2O}=(25.0g)/(231.7g/mole)=0.1079moles`

`\text{ Moles of }C_(10)H_(10)N_4SO_2=\frac{\text{ Mass of }C_(10)H_(10)N_4SO_2}{\text{ Molar mass of }C_(10)H_(10)N_4SO_2}=(50.0g)/(250.3g/mole)=0.1998moles`

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

`Ag_2O(s)+2C_(10)H_(10)N_4SO_2(s)\rightarrow 2AgC_(10)H_9N_4SO_2(s)+H_2O(l)`

From the balanced reaction we conclude that

As, 2 mole of
`C_(10)H_(10)N_4SO_2` react with 1 mole of
`Ag_2O`

So, 0.1998 moles of
`C_(10)H_(10)N_4SO_2` react with
`(0.1998)/(2)=0.0999` moles of
`Ag_2O`

From this we conclude that,
`Ag_2O` is an excess reagent because the given moles are greater than the required moles and
`C_(10)H_(10)N_4SO_2` is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of
`AgC_(10)H_9N_4SO_2`

From the reaction, we conclude that

As, 2 mole of
`C_(10)H_(10)N_4SO_2` react with 2 mole of
`AgC_(10)H_9N_4SO_2`

So, 0.1998 mole of
`C_(10)H_(10)N_4SO_2` react with 0.1998 mole of
`AgC_(10)H_9N_4SO_2`

Now we have to calculate the mass of
`AgC_(10)H_9N_4SO_2`

`\text{ Mass of }AgC_(10)H_9N_4SO_2=\text{ Moles of }AgC_(10)H_9N_4SO_2* \text{ Molar mass of }AgC_(10)H_9N_4SO_2`

`\text{ Mass of }AgC_(10)H_9N_4SO_2=(0.1998moles)* (357.1g/mole)=71.35g`

Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.