Answer:
friction factor, f = 0.025 , hf = 0.9903 m
Step-by-step explanation:
We are given the following:
Diameter, D = 100 mm = 0.1 m
Rate of discharge, Q = 4 L/s = 0.004 m³/s
Length of pipe, L = 300 m
pipe roughness, ε = 0.2 mm
velocity of pipe, v = ?
From rate of discharge = velocity * area, hence
0.004 = v * (π*(0.1/2)²) where area = π*(D/2)²
solving the above expression, we have
v = 0.509 m/s
from Reynold's number = velocity * diameter / dynamic viscosity
i.e Re = V * D / μ
where μ = 10⁻⁶
hence, substituting the values, we have
Re = 0.509 * 0.1 / 10⁻⁶
Re = 50900 and ε/d = 0.2 / 100 = 0.002
from the moody diagram
friction factor, f = 0.025 and I = 300
total friction loss hf = flV²/(2gD)
hf = (0.025 * 300 * 0.509²) / (2 * 9.81 * 0.1)
This evaluates to
hf = 0.9903 m