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Assume the earth to be a nonrotating sphere with mass ME and radius RE. If an astronaut weights W on the ground, what is his weight when he is 2RE above the surface of the earth?

a) W/2

b) W/9

c) W/4

d) W/3

User Theolodus
by
4.4k points

1 Answer

7 votes

Answer:

weight will be become
(W)/(4)

So option (C) will be correct answer

Step-by-step explanation:

We have given mass of the earth is
M_E and radius of earth is
R_E

Acceleration due to gravity on earth is given by
g=(GM_E)/(R_E^2)

Weight is equal to
W=mg, as mass is always conserved so weight is dependent on acceleration due to gravity

Now radius is
2R_E

So acceleration due to gravity is
g_(new)=(GM_E)/((2R_E)^2)=(GM_E)/(4R_E^2)=(g)/(4)

As weight is directly related to acceleration due to gravity

So weight will be become
(W)/(4)

So option (C) will be correct answer

User Andrew Lively
by
4.5k points