Question

What is the magnitude of the force a +29 μC charge exerts on a +3.2 mC charge 50 cm away?

Answer 1

F = 3340.8 N

Step-by-step explanation:

given,

q₁ = + 29 μ C

q₂ = +3.2 mC

distance,r = 50 cm = 0.5 m

Force between two charge = ?

`F = (kq_1q_2)/(r^2)`

k = 9 x 10⁹ N.m²/ C²

`F = (9* 10^9* 29* 10^(-6)* 3.2 * 10^(-3))/(0.5^2)`

F = 3340.8 N

The magnitude of force between the two charges is equal to F = 3340.8 N