Question

6. Describe how you would make 250 mL of a 4.5 M silver nitrate solution. SHOW ALL CALCS.

Answer 1

Dissolve 190 grams of silver nitrate in 250 mL of water.

Explanation:

First, find the moles of AgNO₃ from the volume and concentration.

0.250 L × 4.5 mol/L = 1.125 mol

Next, find the mass of AgNO₃ using the molar mass.

1.125 mol × 170 g/mol = 191.25 g

Rounded to two significant figures, dissolve 190 grams of silver nitrate in 250 mL of water.