![x=9 √(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v300fokhjzsdaq8jshqjygl7ml63hswwjs.png)
Explanation:
The image is attached below.
Given AB = 9
BC = x
AC = y = 18
Note that the given triangle is a right angled triangle.
We know that Pythagoras theorem states that in a right angle hypotenuse is equal to the sum of the squares of other two sides.
Using Pythagoras thereom,
![A C^(2)=A B^(2)+B C^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g88on3dv102mu22u4acurhtx1b84ol2gzf.png)
![18^(2)=9^(2)+x^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qv7js4lryapw5sgxsjg3l085iuaz4wvlhy.png)
![324=81+x^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mjufiy5ethw2zp9yj1x1irq31l85xyhjvz.png)
![x^(2)=324-81](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xduvnx413bkdbegj67viaa1rp0lac6b3uz.png)
![$x^(2)=243$](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xlrbhc5mr87210wgiqobeitj3t06q7m1d7.png)
Taking square root on both sides,
![x=√(9 * 9 * 3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pcu9f1vxjziz85trgfboid9c3te2nturw8.png)
![$x=9 √(3)$](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y46pvvr7osc4dxb8runan74b2npfcfrgn7.png)
Hence, the value of x is
.