Question

an 80 kg cart goes around the inside of a vertical loop of a roller coaster. the radius of the loop is 5m and the cart moves at a speed of 8m/s at the top. what was the force exerted by the track on the cart at the top of the loop?

Answer 1

F= 224 N

Step-by-step explanation:

Given that

mass ,m = 80 kg

Radius ,r= 5 m

speed at the top v= 8 m/s

The force at the top = F

Now by using the Second law of Newton's

`F+mg=(mv^2)/(r)`

Now by putting the values

`F+80* 10 = (80* 8^)/(5)`

Take g = 10 m/s²

`F= (80* 8^2)/(5)-800`

F= 224 N

Therefore the force exerted by the track at the top position will be 224 N.