Question

How many formula units of sodium chloride (NaCl) may theoretically be produced from 13.0 g FeCl3?

Answer 1

`1.445* 10^(23)` formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.

Step-by-step explanation:

Mass of ferric chloride = 13.0 g

Moles of ferric chloride =
`(13.0 g)/(162.5 g/mol)=0.08 mol`

1 mole of ferric chloride has three moles of chloride ions.Then 0.08 moles of ferric chloride will have :

`3* 0.08 mol=0.24 mol` of chloride

`Na^++Cl^-\rightarrow NaCl`

1 mole of sodium ion reacts with 1 mole of chloride ion to form 1 mole of NaCl. Then 0.24 moles of chloride ion will give:

`(1)/(1)* 0.24 mol=0.24 mol` of NaCl

1 mole =
`N_A=6.022* 10^(23)` molecules/ atoms

Number of NaCl molecules in 0.24 moles :

`=6.022* 10^(23)* 0.24=1.445* 10^(23) molecules`

`1.445* 10^(23)` formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.