Amount in Han wallet = $ 80
Amount in amad wallet = $ 13
Amount in karen wallet = $ 20
Solution:
Let "h" be the amount in Han's wallet
Let "k" be the amount in karen wallet
Let "a" be the amount in amad wallet
They have a total of 113 in their wallet
Therefore,
h + k +a = 113 ------- eqn 1
If hans has 4 times the amount of karen
Amount with Han = 4 times the amount with Karen
h = 4k ------- eqn 2
And karen has 7 dollars more than amad
k = 7 + a
a = k - 7 ---------- eqn 3
Substitute eqn 2 and eqn 3 in eqn 1
4k + k + k - 7 = 113
6k - 7 = 113
6k = 113 + 7
6k = 120
k = 20
Substitute k = 20 in eqn 3
a = 20 - 7
a = 13
Substitute k = 20 in eqn 2
h = 4k = 4(20) = 80
h = 80
Summarizing the results:
Amount in Han wallet = $ 80
Amount in amad wallet = $ 13
Amount in karen wallet = $ 20