Question

Approximately 3.54 kJ were used to heat a pot of potato soup, from 25 degrees * C to 100 degrees * C . If the specific heat of potatoes is 3.67 J/g^ C how many grams of potatoes were cooked?

Answer 1

12.9 g potatoes

Step-by-step explanation:

Given data:

Amount of heat used = 3.54 Kj

Initial temperature = 25°C

Final temperature = 100°C

Specific heat capacity of potatoes = 3.67 j/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 100°C - 25°C

ΔT = 75°C

Q = m.c. ΔT

m = Q / c. ΔT

m = 3540 j / 3.67 j/g.°C × 75°C

m = 3540 j / 275.25 j/g

m = 12.9 g