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Which of the following represents the ground state electron configuration for the Mn3 ion?

User Rostam
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1 Answer

6 votes

Answer:


1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2

Step-by-step explanation:

The
Mn^(+3) has 22 electrons arround the nucleous. Its ground state configuration following the diagonal rule is:


1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2

In term of the previous noble gas:


[Ar] 4s^2 3d^2

User EssXTee
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