Question

A light bulb connects to a battery. A second, identical light bulb connects in parallel to the first light bulb. The connecting wires have negligible resistance. When the switch is closed, the original light bulb will:

O no longer light.
O become brighter.
O become dimmer.
O experience no change in brightness.

Answer 1

Answer:d

Step-by-step explanation:

Suppose V is the voltage of battery and R is the resistance of bulb

so Power drop for initial stage

`P_1=(V^2)/(R)`

When another identical bulb of same resistance is applied in parallel so voltage Drop across both the resistor will be same i.e. V

so Power consumed
`P_2=(V^2)/(R)`

so there is no change in power and hence no dip in brightness