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60 points please help me i will appreciate it!

60 points please help me i will appreciate it!-example-1
User Chanee
by
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1 Answer

4 votes

Answer:


\huge\boxed{\sf P =624.678 \ kPa}

Step-by-step explanation:

Given:

Volume = v = 4.34 L

Temp = T = 1.0 °C = 1 + 273 = 274 K

Moles = n = 1.19 mol

Gas constant = R = 0.08206 L atm K⁻¹ mol ⁻¹

Required:

Pressure = P = ?

Formula:

Pv = nRT

Solution:

Rearranging formula


\displaystyle P = (nRT)/(v) \\\\P = ((1.19)(0.08206)(274))/(4.34) \\\\P = (26.8)/(4.34) \\\\P = 6.17 atm\\\\\underline{In \ kPa:}\\\\P =624.678 \ kPa\\\\\rule[225]{225}{2}

User Krlm
by
3.7k points