Answer:
And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.
Step-by-step explanation:
Assuming the following dataset
Temperature (F) Frequency
50-54 2
55-59 0
60-64 4
65-69 12
70-74 7
75-79 5
80-84 1
For this case we can construct the histogram with the following R code.
f<-c(2,0,4,12,7,5,1)
> barplot(f)
And the result is on the figure attached.
And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.