Question

A system has 32 kJ of work performed on it and absorbs 52,000 J of heat. What is the change in the internal energy of the system

Answer 1

84 kJ is the change in the internal energy of the system.

Step-by-step explanation:

According to thermodynamic,Change in energy is sum of heat added to system and work done on the system.:

ΔE = Q + W

Where:

ΔE = change in internal energy

Q = energy added to the system

W = Work done on the system

According to question, we have :

W = 32 kJ = 32,000 J ( kJ=1000 J)

Q = 52,000 J

`\Delta E=52,000 J+32,000 J=84,000 J=84 kJ`

84 kJ is the change in the internal energy of the system.