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43 votes
The perimeter of a rectangle is 30 inches. If its length is three times its width, find the dimensions.

User Rooke
by
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2 Answers

15 votes
15 votes

Answer:

Dimensions are 3.75 * 11.25 inches.

Explanation:

Let the width be x then the length = 3x.

So perimeter = 2(x + 3x) = 30

2x + 6x = 30

x = 30/8 = 3.75 inches = width.

Length = 3* 3.75 = 11.25 inches.

Check:

2 * (3.75 + 11.25)

= 2 * 15

= 30.

User Rajasankar
by
3.2k points
26 votes
26 votes

Answer/Step-by-step explanation:

Given:

The perimeter of a rectangle is 30 inches.

If its length is three times its width, find the dimensions.

Solve:

Let width = x

Let length = 3x

Perimeter = 30

Now equation/Solve =

2x + 2(3x) = 30

2x + 6x = 30

8x = 30

x= 3.75

or x = 3 3/4 {Fraction}

So width is 3 3/4 inches and length is 3x so

3 × 3 3/4 = 11 1/4 inches

Answer:

Length 11 1/4 inches

Width 3 3/4 Inches

Now Find dimensions:

Formula: 2*LW

2 * (3.75 + 11.25)

= 2 * 15

= 30.

Answer = 30

~Lenvy~

User Andrew Guenther
by
3.2k points