Question

A rectangular room is 5 meters longer than it is wide and it’s perimeter is 34 meters fin the dimension of the room

Answer 1

Explanation:

• The length and width is unknown. What we do know is that the length is 5m longer than the width.
• Knowing this we can make the w = x, and the l = x + 5. This is, again, because the width is unknown and the length is the width + 5.
• Perimeter is 2(l + w) (p = 2(l + w)).
• We know the perimeter is equal to 34. Our equation would be 34 = 2(l + w).
• Substituting the length and width for the new variables we created: 34 = 2(x + (x + 5)).
• Simplified a bit this would be 34 = 2(x + x + 5) or 34 = 2(2x + 5)
• Now solve for x.
• x will be equal to your width and x + 5 will be equal to your l

Answer 2

Explanation:

P = 2(L + W)

P = 34

L = W + 5

34 = 2(W + 5 + W)

34 = 2(2W + 5)

34 = 4W + 10

34 - 10 = 4W

24 = 4W

24/4 = W

6 = W <=== 6 meters wide

L = W + 5

L = 6 + 5

L = 11 <=== 11 meters long