Answer:
No balls
Explanation:
Given:
The radius of the ball = 2 m
Height of the ball bin = 3.2 metres
Length of of the ball bin = 1 meters
Width of the ball bin = 1.5 metres
To Find:
How many balls should fit inside the bin = ?
Solution:
Step 1: Finding the volume of the ball
The volume of the ball =
![(4)/(3) \pi r^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/2s02u0rkcnms60d9w26h0za066ix32vsrn.png)
Substituting the value,
=>
![(4)/(3) \pi (2)^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/xzz7j3rz6m9f6ag9z9jbywp2odnt36w3io.png)
=>
![(4)/(3) \pi (8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/94d3fh69f1anm6n7tmsajqjl6a8p2gcslp.png)
=>
![(100.48)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/e5huktdquk45be6ymsrlnzzaubjn2en1tu.png)
=> 33.49
=>33.5 cubic meters
Step 2: Finding the packing space per ball
=>
![190 \% * \text{volume of one ball}](https://img.qammunity.org/2021/formulas/mathematics/high-school/iqyhq2evh1kd9netw30snc4dpyjvm6qzhq.png)
=>
![(190)/(100) * 33.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/r5e321955xe92wsfd4tqmrp7zwhgdaof8g.png)
=>
![1.9 * 33.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/bogzr546ldhlrztqcdh4lgtkpjwovc51og.png)
=>
cubic meters
Step 3: Finding the volume of the container
The volume of the rectangular prism (packing box )
=>
![Length * width * height](https://img.qammunity.org/2021/formulas/mathematics/high-school/z6pp79nkzmrtbtgjtfpgoaki2j49w44hxw.png)
=>
![1* 1.5* 3.2](https://img.qammunity.org/2021/formulas/mathematics/high-school/rxpfbdr2p762empsyep374fnv5ql1b124l.png)
=>4.8 cubic meters
Step 4: Finding the number of ball that can fit in the container
Number of ball =
![\frac{\text{ volume of the container}}{\text{ the packing space per ball}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/i3pxmbtqycekplycown1mijqyhjm3k1fuw.png)
Number of ball =
![(4.8)/(63.65)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qca0rhfzpkhz7h6ydgciq7i6k46w08qlk0.png)
Number of ball = 0.07
No balls can be packed in the bock since the volume of the box is lesser than the packing space required per ball