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How many grams of nitric acid are needed to produce 30.0 g of water?

4Zn+10HNO3=4Zn(NO3)2+NH4NO3+3H2O

User Goba
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1 Answer

1 vote

Answer:

Mass = 32.13 g

Step-by-step explanation:

Given data:

Mass of water produced = 30 g

Mass of nitric acid needed = ?

Solution:

Chemical equation:

4Zn + 10HNO₃ → 4Zn(NO₃)₂ + NH₄NO₃ + 3H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 30 g/ 18 g/mol

Number of moles = 1.7 mol

Now we will compare the moles of water with nitric acid.

HNO₃ : H₂O

10 : 3

1.7 : 3/10×1.7 = 0.51 mol

Mass of nitric acid:

Mass = number of moles × molar mass

Mass = 0.51 mol × 63.01 g/mol

Mass = 32.13 g

User Nadir Laskar
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