221k views
5 votes
If the length of a rectangular field is 12ft less than 6 times it’s width, and perimeter is 158.

User Sevenflow
by
7.9k points

1 Answer

3 votes

Answer:

Therefore the Dimensions of Rectangular field are


Length=66\ feet\\Width=13\ feet

Explanation:

Given:

Let the length of the Rectangular field be ' L '

and Width be 'W'

According to given Condition


L=6W-12

Perimeter = 158 ft

To Find:

L = ?

W = ?

Solution:

Perimeter of Rectangle is given as


Perimeter=2* L+2* W

Substitute 'L' and Perimeter we get


158=2* (6W-12)+2W=12W-24+2W\\\\14W=158+24=182\\\\W=(182)/(14)=13\ feet

Substitute 'W' in L we get


L=6* 13-12=66

Therefore the Dimensions of Rectangular field are


Length=66\ feet\\Width=13\ feet

User Mzimmermann
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories