Solve the system of equations -4x+8y=40−4x+8y=40 and -2x+y=-10−2x+y=−10 by combining the equations.

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Nirmalsinh Rathod · Answer 1 · 2021-08-18T07:23:51+0000

Answer:

Explanation:

It is given that,
$-4x + 8y = 40\\-x + 2y = 10\\x = 2y - 10$ .

Another equation is given by,
$-2x + y = -10\\y = 2x - 10$ .

Putting the value x = 2y - 10, in the second equation, we get
$y = 4y - 20 - 10\\3y = 30\\y = 10$ .

x = 2y - 10 = 20 - 10 = 10