Question

A figure skater begins spinning counterclock-

wise at an angular speed of 3.2 7 rad/s. Dur-
ing a 4.6 s interval, she slowly pulls her arms
inward and finally spins at 7.7 7 rad/s.
What is her average angular acceleration
during this time interval?
Answer in units of rad/s.

Answer 1

The average angular acceleration of the skater is 0.98 rad/s².

Step-by-step explanation:

Given:

Initial angular speed of the skater is,
`\omega_i=3.27\ rad/s`

Final angular speed of the skater is,
`\omega_f=7.77\ rad/s`

Time interval for the change is,
`t=4.6\ s`

We know that, average angular acceleration is given as the ratio of change of angular speed and the time interval.

Therefore, the average angular acceleration is given as:

`\alpha =(\omega_f-\omega_i)/(t)\\\\\\\alpha =(7.77-3.27)/(4.6)\\\\\alpha=(4.5)/(4.6)\\\\\alpha=0.98\ rad/s^2`

Hence, the average angular acceleration of the skater is 0.98 rad/s².