Let p and q be different prime numbers. How many positive factors will (p^2 * q^4)^3 have?

asked Feb 28, 2021 75.8k views

4 votes

by DDR

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4 votes

The answer would be 91.

4.2k points

6 votes

Answer:

Explanation:

p^6×q^12 will have (6+1)(12+1) = 7×13 = 91 positive integer divisors.

Rezaul Karim answered Mar 4, 2021

4.3k points

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