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Let p and q be different prime numbers. How many positive factors will (p^2 * q^4)^3 have?

User DDR
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4 votes
The answer would be 91.
User Christopher Spears
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6 votes

Answer:

91

Explanation:

p^6×q^12 will have (6+1)(12+1) = 7×13 = 91 positive integer divisors.

User Rezaul Karim
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