Question

1.95 kJ of heat is required

to raise the temperature of
500 g of lead from 15°C to its final temperature. What is the final temperature if the specific heat capacity of lead is 130 J/(kg°C)?

Answer 1

45°C

Step-by-step explanation:

We are given;

• Quantity of heat = 1.95 kJ
• Mass of lead = 500 g
• Initial temperature = 15° C
• heat capacity of lead is 130 J/kg°C

We are required to calculate the final temperature;

• We need to know that the quantity of heat is given by the formula;

Q = mass,m × specific heat,c × Change in temperature,ΔT

ΔT = final temperature - initial temperature

We can rearrange the formula to calculate the change in temperature

ΔT = Q ÷ (m×c)

Therefore;

ΔT = 1950 J ÷ (0.5 kg × 130 J/Kg°C)

= 30°C

But,

Final temperature = ΔT + Initial temperature

= 15°C + 30°C

= 45°C

Therefore, the final temperature is 45°C