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What is the rate of decay for the function f(x) =2(0.95)^x ( x is on top of the parentheses)

User Bstpierre
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1 Answer

5 votes

Answer:

The decay rate is 5%.

Explanation:

Let a substance is decaying at the rate of r% per hour from the initial value of P for t hours, then the final value of the substance is given by the function


f(t) = P(1 - (r)/(100))^(t) ........... (1)

Comparing this equation with the original equation given as


f(x) = 2(0.95)^(x) ............ (2) we get,


(1 - (r)/(100)) = 0.95


(r)/(100) = 0.05

r = 5%.

Therefore, the decay rate is 5%. (Answer)

User Argoth
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