Answer:
200.00 mol
Step-by-step explanation:
Given data:
Moles of nitric acid produced = ?
Moles of nitrogen dioxide = 300.00 mol
Solution:
Chemical equation:
3NO₂ + H₂O → 2HNO₃ + NO
Now we will compare the moles of nirtic acid with nitrogen dioxide.
NO₂ : HNO₃
3 : 2
300.00 : 2/3×300 = 199.99 mol
Nearest to 0.01:
200.00 mol