Answer:
Explanation:
Since the segment EF appears tangent to the circle, we are assuming that it it is actually tangent.
This assumption gives us a right triangle with base
(because it the radius of the circle), a perpendicular of
, and a hypotenuse of
; therefore, from the Pythagorean theorem we have
.
Upon expanding the expression on the right side, we get
.
Subtract
from both sides:
,
and solve for