Question

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Answer 1

After 1.5 second of throwing the ball will reach a maximum height of 44 ft.

Explanation:

The height in feet of a ball after t seconds of throwing is given by the function

h = - 16t² + 48t + 8 .......... (1)

Now, condition for maximum height is

`(dh)/(dt) = 0 = - 32t + 48` {Differentiating equation (1) with respect to t}

⇒
`t = (48)/(32) = 1.5` seconds.

Now, from equation (1) we get

h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.

Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)