(x + y)² +r ² = (x+y+r) (x\ + y) {}^(2) + r {}^(2) = (x + y + r) {}^(2)

asked Jul 1, 2021 231k views

3 votes

(x + y)² +r ² = (x+y+r)

$(x\ + y) {}^(2) + r {}^(2) = (x + y + r) {}^(2)$

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3 votes

X=0
Y=0
R=1
R can be two things 1 or 0 but I think one is the answer they are looking for

CalvinR answered Jul 7, 2021

3.0k points

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