Answer:
See below.
Explanation:
6x^2 + 13x - 5 (3x - 1)(2x + 5) 2x + 5
-------------------- = ------------------- = --------- (answer.)
6x^2 - 23x + 7 (3x - 1)(2x - 7) 2x - 7
The (3x - 1) is common to both top and bottom of the fraction so it is cancelled out.
The 2 expressions are factored using the 'ac' method.
6x^2 + 13x - 5:
6 * - 5 = -30 , so we need 2 numbers whose product is -30 and whose sum is + 13.
These are + 15 and - 2 so we write the expression as:
= 6x^2 - 2x + 15x - 5 Now factor this by grouping:
= 2x(3x - 1) + 5(3x - 1)
= (3x - 1)(2x + 5).
The other expression is factored in the same way.