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Calculate oxidation number of C2H2O4​

1 Answer

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Answer:

Step-by-step explanation:

First You must know this

Oxidation number for H = +1 and for O = -2

let C unknown

the total charge for molecule is ZERO

SO =>> 2(X) + 2(+1) + 4(-2) = 0 ( 0 -> for total charge )

so 2X + 2 + ( -8 ) = 0

2X + 2 - 8 = 0 ( Take 8 and 2 to another side and change the sign )

2X = 8 - 2 ( Divide by 2 to calculate the value of x )

X = 8 - 2 ÷ 2

X = 6 ÷ 2 = 3

So the oxidation number for one Carbon is +3 , for two is +6

2C = +6 , 2H = +2 , 4O = -8 ( the total Charge is ZERO ( 8-8 = 0 )

GOOD LUCK

User Hamid Rouhani
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