186k views
2 votes
Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15.

2 Answers

4 votes
15•3 is your answer!
User Piyin
by
4.4k points
5 votes

Considering the definition of perpendicular line, the equation of the perpendicular line is y= 3/5x -2.

Linear equation

A linear equation o line can be expressed in the form y = mx + b.

where

  • x and y are coordinates of a point.
  • m is the slope.
  • b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

Perpendicular line

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

Equation of perpendicular line in this case

In this case, the line is 5x+3y=15. Expressed in the form y = mx + b, you get:

3y= 15 - 5x

y= (-5x +15)÷ 3

y= -5/3x +5

If you multiply the slopes of two perpendicular lines, you get –1. So:

-5/3× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (-5/3)

slope perpendicular line= 3/5

The line passes through the point (5, 1). Replacing in the expression for a line:

1= 3/5× (5) + b

1= 3+ b

1 -3 = b

-2 = b

Finally, the equation of the perpendicular line is y= 3/5x -2.

User Adam Colvin
by
4.7k points