Question

Please help with this algebra problem!!

Answer 1

For one Fredburger, one Milk Shake and two order of Fries, we pay $4.34

Step-by-step explanation:

Let us assume the cost of Fredburger as B, cost of Milk Shake as M, and cost of Order of Fries as Y.

As mentioned in the Question:

`B + M + Y = $3.72` ----------- Equation 1

`B = M + 2 * Y`, ----------- Equation 2

`3 * M = B + Y`, ----------- Equation 3

Let us assume that we have to pay $X for one Fredburger, one Milk Shake and two order of Fries.

`B+M+2 * Y = $X`, consider this as Equation 4

Substituting Equation 3 into Equation 1:

`B + M + Y = $3.72`

`3 * M + M = $3.72`

`4 * M = $3.72`

`M = (3.72)/(4)`

M = $ 0.93

Substituting value of M in Equation 2,

`B = M + 2 * Y\\\\B = $0.93 + 2 * Y ------ Equation\ 5`

Substituting value of M in Equation 3,

`3 * M = B + Y`

`3 * $0.93 = B + Y`

`B + Y = $2.79` ------------ Equation 6

Substituting Equation 5 in Equation 6,

`B + Y = $2.79 \\ \\$0.93 + 2 * Y + Y = $2.79`

`3 * Y = $2.79 - $0.93`

`3 * Y = $1.86`

`Y = (1.86)/(3)`

Y = $0.62

Substituting value of F in Equation 6,

`B + Y = $2.79`

`B + $0.62 = $2.79`

`B = $2.79 - $0.62`

B = $2.17

Substituting values of B, Y, and M in Equation 4,

`B+M+2 * Y = $X`

`$2.17 + $ 0.93 +2 * $ 0.62 = $X`

`$2.17 + $ 0.93 + $1.24 = $X`

$X = $4.34