Answer:
The distance of needle cover as it rotate is 0.700688 cm
Explanation:
Given as :
The length of the needle = r = 24 cm
The needle is rotated at angle = Ф = 96°
The distance of needle cover as it rotate = length of arc made = l cm
The radius of arc = length of needle = r cm
Now, According to question
The distance of needle cover as it rotate =
![(\Pi * radius* \Theta )/(180^(\circ))](https://img.qammunity.org/2021/formulas/mathematics/high-school/yzqtdbobjhztrizful62bzy0x7ol7mei7p.png)
where , π = 3.14
Or, l =
![(\Pi * r* \Theta )/(180^(\circ))](https://img.qammunity.org/2021/formulas/mathematics/high-school/kbk49yomk2081qbfuch2sqp712td5y4hfy.png)
Or, I =
![(3.14 * 24 cm* 96^(\circ) )/(180^(\circ))](https://img.qammunity.org/2021/formulas/mathematics/high-school/wzqzqenl17yijhl2396y1mgq55s4lgkgyu.png)
Or, l = 75.36 × 0.533°
∵ 180° = 3.14 radian
So, 0.533° = 0.0092978
So, l = 75.36 × 0.0092978
∴ l = 0.700688 cm
So,The distance of needle cover as it rotate = l = 0.700688 cm
Hence, The distance of needle cover as it rotate is 0.700688 cm Answer