Question

5. In a physics lab, an artifact is dropped from the roof of the school building, 98 feet above the ground. The height ℎ (in feet) of the ball above the ground is given by the function ℎ 푡 = –16푡 ' +98, where 푡 is the time in

Answer 1

The function will be,

`h = (98 - 16 * t^(2))` (in feet)

Explanation:

We know that acceleration due to gravity in F.P.S system is given by,

`32 \frac {{\txtrm}{ft}}{{\txtrm}{second^(2)}}` and if a body is dropped from a height of
`h_(1)` feet to fall to the ground then after t seconds it's height above the ground will be given by,

`h = (h_(1) - \frac {1}{2} * g * t^(2))` feet [where the acceleration due to gravity is given by g] provided it is greater than or equal to zero.

here,
`g = 32 \frac {{\txtrm}{ft}}{{\txtrm}{second^(2)}}`

and
`h_(1) = 98` feet

So,

`h = (98 - \frac {1}{2} * 32 * t^(2))`

⇒
`h = (98 - 16 * t^(2))` [in feet]