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3 votes
Given: LN ⊥ KM

LN = 16 ft

m∠K = 25°,m∠M = 55°

Find: Radius R

Given: LN ⊥ KM LN = 16 ft m∠K = 25°,m∠M = 55° Find: Radius R-example-1
User Puetzk
by
5.7k points

2 Answers

6 votes

Answer:

Full decimal:

~ 23.10879

User Rahul Kushwaha
by
6.8k points
3 votes

Answer:

23.1 ft

Explanation:

Consider right triangle LMN. In this triangle,


m\angle M=55^(\circ)\\ \\LN=16\ ft

By sine definition,


\sin \angle M=\frac{\text{Opposite leg}}{\text{Hypotenuse}}=(LN)/(LM)=(16)/(LM)\\ \\LM=(16)/(\sin 55^(\circ))

In triangle KLM, by sine theorem,


(LM)/(\sin \angle K)=2R,

where R is the radius of circumscribed circle.

Therefore,


R=(1)/(2)\cdot ((16)/(\sin 55^(\circ)))/(\sin 25^(\circ))=(8)/(\sin 55^(\circ)\cdot \sin 25^(\circ))\approx 23.1\ ft

User Techie Joe
by
5.8k points