Question

Find the zeros of y= x2 - 6x - 4 by completing the square.

Answer 1

x = 3 - √13, 3 + √13.

or

-0.61, 6.61 to the nearest hundredth.

Explanation:

x^2 - 6x - 4 = 0

(x - 3)^2 - 9 - 4 = 0

(x - 3)^2 = 13

x - 3 = +/-√13

x = 3 - √13, 3 + √13.