The expression for y in terms of "a" when value of x is doubled is
![y_1=4a](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wq9htyg1lzfacvltl035btzdpmunnt7lw0.png)
Solution:
Given that,
y is directly proportional to
![x^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jbdxz1mpqo3eyt55vfyhxh768qjd5to40z.png)
Therefore,
![y \propto x^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hku3x17sv53uhb4z890w8hgm07uw4084i5.png)
![y = kx^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/clbkhw8q8oe11xx6zcdk3yyxerxrmjqrnc.png)
Where "k" is the constant of proportionality
y = a for particular value of x
Therefore,
--------- eqn 1
We have to find when x is doubled
x is doubled means 2x
Let it be
![y_1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/efy8mchz79kehc7m8uvfptw1w02dxxbag6.png)
Hence we get,
--------- eqn 2
Substitute value of k from eqn 1, we get
![y_1=(a)/(x^2) * 4x^2\\\\y_1=4a](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lef1h2cmdlnxvluqczcz22sylinzzgshhx.png)
Thus expression for y in terms of "a" when value of x is doubled is
![y_1=4a](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wq9htyg1lzfacvltl035btzdpmunnt7lw0.png)