Answer:
The graph in the attached figure
Explanation:
we have
![y=3√(x+2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hluo4u01ikq1fo29iyp2n2tzzlamemaqli.png)
Remember that the radicand must be greater than or equal to zero
so
![x+2\geq 0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jktudvf1jcmvzh0gc73xgfjkxuemt797wu.png)
solve for x
subtract 2 both sides
![x\geq -2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k9w4co2eb9hcl4iteuneed9fedow5pl7j2.png)
The domain is the interval [-2,∞)
All real number greater than or equal to -2
For x=-2
![y=3√(-2+2)=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7ev3fs8nkfbifaa8k7yrqd0ulsptv5aot8.png)
so
The range is the interval [0,∞)
All real number greater than or equal to 0
Find the y-intercept
Remember that the y-intercept is the value of y when the value of x is equal to zero
For x=0
![y=3√(0+2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/to3fxo4g1wwusrrrzg14vs3y8oi5vppi0z.png)
![y=3√(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cp4psbxx9mgi3r00sc4pijg1xgr151dipb.png)
![y=4.243](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8u712uem0pndyysdou4x1z4dyro1ltqdu1.png)
The y-intercept is the point (0,4.243)
therefore
The graph in the attached figure