Question

A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y = ________.A. 7/11B. 3/4C. 7/4D. 4/3E. 11/7

Answer 1

D.
`(4)/(3)`

Explanation:

We have been given that a bag contains x blue chips and y red chips. The probability of selecting a red chip at random is 3/7. We are asked to find the
`(x)/(y)`.

`\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}`

`P(\text{Red})=\frac{\text{Number of red chips}}{\text{Total number of chips}}`

`P(\text{Red})=(y)/(x+y)`

Since we are told that probability of selecting a red chip at random is 3/7, so red balls are 3 and total balls are 7:

`P(\text{Red})=(3)/(x+3)`

Since total balls are 7, so we will get:

`x+3=7\\x=4`

Upon substituting
`x=4\text{ and } y=3` in expression
`(x)/(y)`, we will get:

`(4)/(3)`

Therefore, the value of
`(x)/(y)` is
`(4)/(3)` and option D is the correct choice.