The length of rectangle is 58 feet and width of rectangle is 49 feet
Solution:
Given that rectangle has a perimeter of 214 feet
Let "l" be the length of rectangle
Let "w" be the width of rectangle
It's length is 9 feet longer than its width
length = 9 + width
l = 9 + w ----- eqn 1
The perimeter of rectangle is given as:
perimeter = 2(length + width)
Substituting the given values we get,
214 = 2(l + w)
Substitute eqn 1 in above expression
214 = 2(9 + w + w)
214 = 2(9 + 2w)
214 = 18 + 4w
4w = 214 - 18
4w = 196
w = 49
Thus length = 9 + w = 49 + 9 = 58
Thus length of rectangle is 58 feet and width of rectangle is 49 feet