Question

60g of a compound on analysis gave 24 g C, 4 g H and 32 g O. What's the emperical formula?​

Answer 1

`\text{Given,}`

`\text{Mass of C = 24g(w) for C}`

`\text{mass of H= 4g(w) for H and mass of C= 32g(w)}`

`\text{for O( ∵n= w/m)}`

`\therefore \text{ moles of C =} (24)/(12 ) = 2`

`\text{moles of H =} (4)/(1) = 4`

`\therefore \text{ moles of O=} (32)/(16) = 2`

`\text{Thus, Simple Ratio is= 2:4:2 also be written as 1:2:1}`

`\text{Hence, Emperical Formula=} \text{CH}_2 \text{O}`

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