Answer:
substance A will be the limiting reactant. Substance B will be in excess. Option E is correct.
Step-by-step explanation:
Step 1: Data given
We mix 2 units (moles) of A with 6 units(moles) of B
Step 2: The balanced equation:
2A + 3B → C + 3D
Step 3: Determine the limiting reactant
For 2 moles of A we need 3 moles of B to produce 1 mol of C and 3 moles of D
IF A would be the limiting reactant, it means it would completely be consumed ( 2 units).
B is in excess. there would react 2 *3/2 = 3 units.
There would remain 6 - 3 = 3 units of B
If B would be the limiting reactant, it means it would completely be consumed (6 units).
A would be in excess, there would react 6 * 2/3 = 4 units.
This would be impossible.
We can decide that substance A will be the limiting reactant. Substance B will be in excess. Option E is correct.