Question

For how many integer values of $n$ between 1 and 1000 inclusive does the decimal representation of $\frac{n}{1400}$ terminate?

Answer 1

142 integers

Step-by-step explanation:

For the given expression "n/1400", there exists a terminating expansion if and on if 2 and 5 are in the denominator. Therefore:

The denominator "1400" can be broken down into (2^3)*(5^2)*7. Then we need a number that can be divided by 7 and is between 1 and 1000. The number is 994 and the number of possible integer values = 994/7 = 142.