Question

Can someone answer these few questions please?

1.27*10^15 atoms Si to mol Si
8.65*10^25 molecules CCl4 to mol CCl4
5.80 mol Ca to atoms Ca

Answer 1

2.10x10⁻⁹ moles of Si, 143.7 moles of CCl₄, 3.49x10²⁴ atoms

Step-by-step explanation:

These is the relation:

NA (6.02x10²³) ⇒ 1 mol of particles (it can be, atoms or molecules)

This are the rule of three:

NA of atoms occupies 1 mol of Si

1.27x10¹⁵ atoms will occupy (1.27x10¹⁵ .1 ) / NA = 2.10x10⁻⁹ moles of Si

NA of molecules are contained in 1 mol of CCl₄

8.65x10²⁵ molecules are contained in (8.65x10²⁵ .1)/ NA = 143.7 moles

1 mol of Ca has NA atoms

5.80 moles of Ca will have (5.80 . NA) = 3.49x10²⁴