Answer:
1x10⁻⁴ moles of Cl⁻ in NaCl solution
2x10⁻⁴ moles of Cl⁻ in MgCl₂ solution
3x10⁻⁴ moles of Cl⁻ in AlCl₃ solution
Step-by-step explanation:
Let's produce the reactions of each salt
NaCl → Na⁺ + Cl⁻
0.1 m 0.1m
MgCl₂ → Mg²⁺ + 2Cl⁻
0.1m 0.2m
AlCl₃ → Al³⁺ + 3Cl⁻
0.1 m 0.3m
0.1, 0.2 and 0.3 are the moles of each chloride in each solution and this moles are added to one liter of solvent.
1 L = 1000mL
Let's prepare the rule of three for each
1000 mL ____ 0.1 m ____ 0.2 m _____ 0.3m
1 mL______ 1x10⁻⁴ m ___ 2x10⁻⁴ m _____ 3x10⁻⁴ m