Answer:
option (a) 80 Pa
Step-by-step explanation:
Data provided in the question:
v = 4 m/s
Distance between the plates, t = 5 mm = 5 × 10⁻³ m
Specific gravity, s = 0.80
Kinematic viscosity, ν = 1.25 × 10⁻⁴ m²/s
Now,
μ = sν
= 0.80 × 1.25 × 10⁻⁴
= 0.1 kg/m.s
average shear stress, τ = μ × [ v ÷ t]
= 0.1 × [ 4 ÷ 5 × 10⁻³ ]
= 80 Pa
Hence,
option (a) 80 Pa