A force of 50 N is applied to the end of a lever, which is moved a certain distance. if the other end of the lever moves one-third as far, how much force is exerted?

Question

asked Sep 11, 2021 138k views

1 Answer

Alptigin Jalayr · Answer 1 · 2021-09-15T20:32:56+0000

Answer:150 N

Step-by-step explanation:

Given

Force applied at one end of lever is
$F_1=50\ N$

Distance moved is
d_1=d

Distance moved on other end is
d_2=(d)/(3)

work done by the force is given by

$W=F\cdot d$

$W=F_1\cdot d_1=F_2\cdot d_2$

$F_2=(d_1)/(d_2)\cdot F_1$

$F_2=(3d)/(d)\cdot 50$

$F_2=150\ N$