Question

A force of 50 N is applied to the end of a lever, which is moved a certain distance. if the other end of the lever moves one-third as far, how much force is exerted?

Answer 1

Answer:150 N

Step-by-step explanation:

Given

Force applied at one end of lever is
`F_1=50\ N`

Distance moved is
`d_1=d`

Distance moved on other end is
`d_2=(d)/(3)`

work done by the force is given by

`W=F\cdot d`

`W=F_1\cdot d_1=F_2\cdot d_2`

`F_2=(d_1)/(d_2)\cdot F_1`

`F_2=(3d)/(d)\cdot 50`

`F_2=150\ N`