Answer:
The temperature change is 12.5 °C
Step-by-step explanation:
Step 1: Data given
20950 joules of heat are added to a container
Mass of water = 400 grams
Specific heat of water = 4.184 J/g°C
Step 2: Calculate temperature change
q = m*c*ΔT
⇒ with q = the heat added to the container = 20950 J
⇒ with m = the mass of water = 400 grams
⇒ with c = the specific heat of water = 4.184 J/g°C
⇒ with ΔT = the change of temperature
20950 J = 400 * 4.184 * ΔT
ΔT = 12.5 °C
The temperature change is 12.5 °C